Nice result!
Ok, just for fun: I'll try to make a quick back-of-an-envelope calculation and see if we can make an educated guess...
Let's use the old Sunny 16 rule, and its equivalent for moonlight, which also gives us an estimate for difference in light between day and night[0]:
> Daylight (sunny day): Correct exposure for this case is given by the Sunny 16 Rule: 1 / ISO [seconds] @ f/16. So at ISO 100, a typical exposure is 1/125 @ f/16 (that's 1/3 stop less exposure than the rule calls for, but it's the closest standard shutter speed.)
> Full moon: to get an equivalent exposure at night with a full moon, the rule is: 1 / ISO [days] @ f/4. That's right, DAYS. For ISO 100, that means 1/100 of a day @ f/4.
> That works out to something like 14.7 minutes; I just round it up to 15 minutes. So 15 minutes @ f/4, or FOUR HOURS @ f/16.
> That's 21 stops difference from sunlight to moonlight.
So on a sunny day you need f/16, 100 ISO, shutter speed 1/100.
flickr says you shot at f/5.6, unknown ISO (I'll go with quasi-conservative 6400 ISO), 5 seconds.
Aperture increased by 1.5 stops
ISO increase by 6 stops
500x longer shutter time => log2(500) -> 2^9 = 512 => bit less than 9 stops.
So that's between 16-17 stops of extra light sensitivity
That's five stops short of the 21 stops mentioned above. However, we're not aiming for a properly exposed single picture, we're aiming for minimum exposure to capture a signal!
Even the first digital SLRs had a dynamic range of five to six stops, so theoretically should be able to capture something in the shadow regions. Nowadays ten stops is about the norm I believe, with some of the better cameras going up to twelve. So that should clearly be above the minimum signal required
Also, the moonlight-rule above is very conservative: it's about exposing a scene in moonlight, not about capturing stars. Stars are light sources themselves, and probably brighter than objects reflecting moon light, even in a full moon. Also, the rule-of-thumb was based on film, which actually suffered from something called "reciprocity failure"[1] so it might exaggerate the required exposure.
So yes, this should work out fine, and as your picture shows it clearly does :)
[0] https://www.flickr.com/groups/11947580@N00/discuss/721576207...
[1] https://en.wikipedia.org/wiki/Reciprocity_(photography)#Reci...