The Aggregate Magic Algorithms (2015)
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> Clearly, floor of base 2 log of x is (WORDBITS-lzc(x)).
Uh, is it?
> Clearly, floor of base 2 log of x is (WORDBITS-lzc(x)).
Yes. Because the 1st bit indicates the MSB of the number and the way binary works
If you have only one bit set, then WORDBITS-lzc(x) is log2(x). If you have less significant bits enabled that won't be enough to bump the floor to the next number
Grrr x)
The "clearly" stuff is just shorthand for "I assume you know this because its foundational to understanding the thing were talking about now / or I'm too lazy to explain this now / or this is so far off-topic that this isnt the place / etc. etc" . Nothing more - it can be read as arrogance on the authors part but I think thats an uncharitable interpretation.
> Uh, is it?
Of course, that is intuitively obvious to even the most casual observer. ;)
http://www.urbandictionary.com/define.php?term=intuitively%2...
Basically, you're using a binary representation, so everything is in powers of two. Let's just talk integers. 2^n is just the nth bit set and a bunch of zeros. Every number between 2^n and 2^n+1 has the nth digit set and some lower digits. The log base 2 is between n and n+1. So the floor is n. So, biggest digit set=floor of log base 2.
Once you've grasped that principle, the exact details are, in fact, clear. :)
[0] http://web.stonehill.edu/compsci/History_Math/math-read.htm
HN discussion: https://news.ycombinator.com/item?id=14232977
https://www.reddit.com/r/programming/comments/4vctor/.../d5x...
https://cs.stackexchange.com/a/74888/16408
The first asked
> Extra-extra credit can be earned for finding an algorithm that takes no more than O(log N) space and no more than O(log N) time, where N is the number you are seeking for.
and the bit magic made it O(1) space and time. The second was on similar lines.
Unfortunately the bit fiddling at my day job tends to be a bit tamer ;).
https://stackoverflow.com/q/40141793/1763356
The bit math is milder, but it still comes in handy.
On my wishlist: updated versions of these for modern architectures and SIMD. Full disclosure: am Intel employee. That said, modern chips of all strips (x86, ARM64) all can do some amazing things with low-cost SIMD and bit-manipulation instructions. It would be interesting to see what smart folks come up with using these. Obviously you can make the 'bit extract' function really boring with PEXT, but what cool tricks can you do when you start with AVX2 and BMI1/2 as a baseline?
MOR $0,#0102040810204080,$0 MOR $0,$0,#0102040810204080
(Although that constant will be placed in a register, but you can use the same constant twice.)
Some of these are absolutely suspect. Now, these are all architecture specific: my results below are for gcc, targeting the Intel chip in the MBP in my lap. (Of course, some of the article's code samples assume certain things about an architecture, and are not portable.)
For example,
> Absolute Value of a Float
> IEEE floating point uses an explicit sign bit, so the absolute value can be taken by a bitwise AND with the complement of the sign bit. For IA32 32-bit, the sign bit is an int value of 0x80000000, for IA32 64-bit, the sign bit is the long long int value 0x8000000000000000. Of course, if you prefer to use just int values, the IA32 64-bit sign bit is 0x80000000 at an int address offset of +1. For example:
double x;
/* make x = abs(x) */
*(((int *) &x) + 1) &= 0x7fffffff;
First, this is undefined behavior. The portable way to do this is fabs(), which is part of the standard library. For me, calling fabs() compiles to a single instruction: andps LCPI1_0(%rip), %xmm0
where LCPI1_0 is .quad 9223372036854775807 ## 0x7fffffffffffffff
.quad 9223372036854775807 ## 0x7fffffffffffffff
fabs() compiled down to essentially the same bitwise &, in assembly, that the article is doing. The article's "advice" also gets compiled to exactly the same instruction & set of constants, which I actually find way more interesting.> Integer Constant Multiply
> Given an integer value x and an integer or floating point value y, the value of xy can be computed efficiently using a sequence derived from the binary value of x. For example, if x is 5 (4 + 1):*
y2 = y + y;
y4 = y2 + y2;
result = y + y4;
> In the special case that y is an integer, this can be done with shifts: y4 = (y << 2);
result = y + y4;
Compilers will do this for you, today, automatically. In the example case of multiplying by 5, gcc will do better than the article's code, by using lea cleverly: leal (%rdi,%rdi,4), %eax
gcc also compiles the article's shift-then-add strategy to exactly the same leal.The article mentions this optimization again, later,
> Shift-and-Add Optimization
> Rather obviously, if an integer multiply can be implemented by a shift-and-add sequence, then a shift-and-add sequence can be implemented by multiplying by the appropriate constant... with some speedup on processors like the AMD Athlon. Unfortunately, GCC seems to believe constant multiplies should always be converted into shift-and-add sequences, so there is a problem in using this optimization in C source code.
The above leal instruction was the output of GCC, so this is obviously wrong. One can maybe say the article is old, but I'm pretty sure GCC has had the "use leal to do constant multiplies" optimization for over a decade now, but then, perhaps the article is that old. If so, the advice would appear to no longer apply.
Write it the obvious, readable way first. If you decide to optimize at the level this article is discussing, you should be reading the assembly to see if your optimizations will have any effect.
But not all of them are bad. The "is this unsigned integer a power of 2" code is correct, I believe, and if you understand binary, not that hard to understand.
int min(int x, int y) { return y < x ? y : x; }
..most compilers will produce something very much like the following for x86-64 (from Compiler Explorer https://gcc.godbolt.org using -Ofast -march=haswell): min(int, int):
cmp esi, edi
mov eax, edi
cmovle eax, esi
ret
Compare that to the generated instructions for the algorithm listed in the "Integer minimum or maximum" section (x+(((y-x)>>(WORDBITS-1))&(y-x))): min(int, int):
sub esi, edi
mov eax, esi
sar eax, 31
and eax, esi
add eax, edi
ret
It's not immediately obvious to me which one is likely to be faster (I'm not an expert on x86-64 assembly).