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Regarding 5, no, it's five bytes (b8 01 00 00 00) for movl $1,%eax. If you actually have a 64-bit immediate, just the immediate itself would be 8 bytes, and the actual instruction is 10 bytes.

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MOV RAX, 1 is seven bytes: 48 C7 C0 01 00 00 00

The parent has a good point actually, because "mov eax,1" automatically zero-extends in 64-bit mode.

It's still one byte longer than the equivalent AArch64 instruction, though.

Fine. If you are really into getting the shortest instruction, try "xorl %eax,%eax" then "incl %eax" which is four bytes (31 c0 ff c0).

push $1/pop %eax (6a 01 58) is shorter, but perhaps not the best idea.

Actually, there is no 32-bit pop instruction in x86-64 mode. Your code won't work.

You're right: it should be pushq $1/pop %rax (which is also three bytes, although there will be a prefix byte for registers r8 through r15).

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