Thanks for the response. My question is how does fixed point relate to the incomplete theorems and decidability?
The proof, if you are interested, is not difficult. Let sub be the function that describes, via codes, substituting the (numeral n_ of the number) n for a free variable v of a formula χ : sub(<χv>, n_) = <χn_>. Then the PROOF is: consider ψ(sub(v,v)), call it θv, let m be <θv> and let φ be θm_. Then, provably, φ <=> ψ(sub(m_,m_)) <=> ψ(sub(<θv>,m_)) <=> ψ(<θm_>) <=> ψ(<φ>). Ta-da!
Goedel used this to get the "formula that says I am not provable", φ <=> not Prov(<φ>).