It's trivial to explain:
x^n = x(x^2)^((n-1)/2), if n is odd
= (x^2)^(n/2) , if n is even
Knowing that (or having figured that out yourself if an interview was your first exposure to this problem), it's even more trivial to implement, making it a math quiz far more than a programming exercise. (Though I later turned it into a programming exercise entirely to exploit an arbitrary eye bleedecution bug in the human brain: https://gist.github.com/LnxPrgr3/7154873d3eb8b1e5960851628c7...)Maybe that's what they intended. It's certainly legit if the job will have you actually doing, rather than applying, math. Except that it concludes you can math if you're smart enough to pretend to derive the answer you memorized after encountering it before. You might accidentally hire a bunch of crypto nerds.