HN
Hacker News
Top
New
Best
Ask
Show
Jobs
Comment by JumpCrisscross | Hacker News Reader
Parent
Full thread
JumpCrisscross
·
Could you please expand on your kT ~ 0.02 calculation?
View on HN
inlineint
·
Sorry, it was of course 0.02 eV, not just 0.02 :)
k = 1.38e-23 J/K = 8.6e-5 eV/K, so kT = 0.025 eV for T = 300 K.
baq
·
of course ;)
Reply on news.ycombinator.com