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Comment by coherentpony | Hacker News Reader

    grep -rl 500 .

wasn't accepted. Am I wrong or is it wrong?

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Only filenames matching access.log should be returned.

Unfortunately, since shopt globstar is disabled I ended up needing to do this:

    grep 500 $(find . -type f -iname "access.log*")

You could also include "shopt -s globstar; " at the beginning of your line.

grep -r 500 --include access.log

That returns the filenames in the format "./access.log" but it wanted "access.log". It's a bug.
I used echo -e 'access.log\naccess.log.1\nREADME'. :D

Hahahaha I did the exact same thing

Gotcha. Thanks.

You are: grep matches strings, not integers.
grep -rl '500'
works just fine.

There is no concept of an integer on an argument vector. Quoting in bash just escapes IFS characters (usually whitespace) to control whether to include them in a given argument on the vector, but these arguments (as passed to exec) are always character strings (with or without quoting).

Interestingly enough
grep -rl "500" .
doesn't work because it returns with the "./".

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