0 = 12 + 34 − 56 − 7 + 8 + 9.
1 = 1^23456789.
2 = 123+4−56−78+9.
3 = 123 − 45 − 6 − 78 + 9.
And then in decreasing order 0 = 98−7−6−54−32+1.
1 = 98−76−54+32+1.
2 = 9+87−65+4−32−1.
3 = 98−76−5+4+3−21.
That this is possible at all is counter-intuitive to me, and hence fascinating. Even more fascinating is that he does not have a solution for 10958 in the ascending case.