Physicists demonstrate existence of new subatomic structure
las.iastate.edu
las.iastate.edu
1. practical observation (optional)
2. a hypothesis (either from first principles or to explain a practical observation)
3. testing that hypothesis
4. establish as theory if it holds up, or mark as "known to not be true" if it doesn't.
You've not scienced until you're done with step 3, because step 2 on its own cannot "confirm" or "verify" anything found in step 1.The most important part is to confirm that a theory is not accidental, giving simulations a disadvantage: it is far easier to accidentally find parameters in a simulation than it is when you're on paper from first principles - even if that paper's Mathematica or R. You can always find some set of values, parameters, and functions that result in the thing you're looking for, so once you find such a set, you then still need to go back to the lab, verify that it holds up, and have others verify it holds up, too.
(the result of a single study is merely a very interesting anecdote. It's not data until your findings can be reproduced, and it's not a scientific theory until it's proven to hold up. Until then it's just a hypothesis)
10 minutes is an eternity and 5×10^(-22) seconds is closer to what I'd consider 'very unstable'
I don't know how fast these particles were going in the experiment, but if they were going at the speed of light, then the tetraneutron would make it 150 femtometres from the site of the collision before decaying. By way of comparison, neutrons and protons are 1 - 2 fm across, and a uranium nucleus is 15 fm across [i]. So if the tetraneutron was actually going at a tenth of the speed of light, it would barely make it a nucleus's diameter away before exploding.
As observers, the detectors would see precisely what we expect if we calculate the distance using the detector's proper time when compared with the distance we experimentally measure.
The half life of a static tetraneutron is (theoreticaly) 5E-22s.
If you are at a laboratory and the tetraneutron is moving at relativistic speed, the apparent half life in the laboratory frame will increase substantially.
To calculate the distance that the tetraneutron will travel you must multiply the velocity x the apparent half life. I.E
d ~= v * 1/(1-v^2/c^2) * t_hl
where t_hl = 5E-22s = the half life of the tetraneuton
not the classic version that is
d_clasic_wrong = v * t_hl
For a more detailed explanation, with numbers and graphic you all can see the analogue experiment with muons: http://hyperphysics.phy-astr.gsu.edu/hbase/relativ/muon.html
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Anyway, IIRC a half life of 5E-22s is still very small. IIRC you can use a bubble chamber or something similar to see the trajectory of the particles. You can only see a collision and examine the debris and you will note that when the collision has some specific energy you will get an unexpected excess of collisions. You only can examine the direction and energy of the debris to make a good guess of the intermediate steps of the collision and discover that for a very short time you had a tetraneutron.
In retrospect perhaps the parent comment was saying theoretically it could travel any distance which is true, but doesn't really help in estimating whether it could clear nuclear radii or not.
>four neutrons together can form a resonance, a structure stable for a period of time before decaying.
Quite on the contrary.
No, it's where the possible is often portrayed as impossible by popular reporting all the time.
https://home.cern/about/updates/2016/05/theory-theoretical-p...