Not being used to C syntax, I took this as a typo at first:

    indirect = &(*indirect)->next;

The position of the parentheses make it look like you're dereferencing only (* indirect). But on second look, you need the parens there so that it's (* indirect)->next as opposed to indirect->next. Then the & operates on the whole thing. I'd be tempted to wrap it in a second set of parens for clarity, but perhaps it's entirely obvious to a programmer who's actually used to using pointers. IE:

    indirect = &((*indirect)->next);