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How did you solve the reflexive? I'm not getting at anything :(

I broke things to do it

[] - {}

Yeah, tricky one. NaN works though. Because NaN == NaN = false

`NaN`

NaN != NaN. It's how you're supposed to test for NaN, apparently.

Or use isNaN

reflexive( function() {return ++window.x;}() )

I don't think so

Infinity - Infinity

Another version, also 3 characters: 0/0

!0 - 2 chars 1>0 - 3 chars

Ah. 2 distinct characters now.

I used !!1

Yup. !0