Check Widening in LLVM
playingwithpointers.com
playingwithpointers.com
How so? Why does the test change?
In other words, the general optimization is to convert
bool A = condition();
if (!A) { f(A); }
to: bool A = condition();
if (!A) { f(false); }
i.e., that we can assume an if-condition is true within the body of that if-statement. The problem is that the check-widening reuses the body of the if-statement: the code bool A = condition();
if (!A) { f(A); }
bool B = condition();
if (!B) { f(A); }
is converted by check-widening to the first snippet above, which then becomes the second. Sanjoy's observation is that guard-widening is almost correct (we still want to pursue this route) because `f` (the deoptimization escape) is really what we want to call in both cases, but we just need to get the value of `A` right by somehow letting the optimizer know that we're reusing the if-body and that it can't assume anything about the condition that got us there.Also, this is really really clever and I enjoyed the post, OP!