I think it would be possible to create a generalised `zipN` function, using the Haskell printf trick[0], but it would be a lot of complication for little benefit. It's rare that you need to merge that many streams at once, and adding a single digit is not a huge hassle in those cases. Also I'd probably consider splitting the operation up into stages if I was using anything higher than `zipWith3`.

[0]http://stackoverflow.com/questions/7828072/how-does-haskell-...