Hacker News Reader

Comment by avyfain | Hacker News Reader

Interesting, had not considered that at all. So basically, to ensure the old reference is not released, just naming it would do the trick? AKA:

    >>> some_unbound_method = A.b
    >>> hex(id(some_unbound_method))
    '0x104e2c0a0'

Yep, that's right. To lay out the example the way you did in the article, it would look like:

    >>> foo = A.b
    >>> bar = A.b
    >>> hex(id(foo))
    '0xdeadbeef'
    >>> hex(id(bar))
    '0xdecafcab'
    >>> foo is bar
    False