How much oxygen for a person to survive in an air-tight enclosure? (2004)
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Even supplying fresh O2 into the room from a cylinder won't save him, unless someone finds a way to remove CO2 from the room.
78.1% nitrogen
20.9% oxygen
0.93% argon
0.039% carbon dioxide
Carbon dioxide, in very approximate figures, is unpleasant at 0.5%, dangerous at 5%, fatal at 10%.I took a lungful (choked on the first breath, coughed, started really choking) of air heavy with co2 in a pub cellar once. Only because I fainted on top of the kegs above the co2 saturated air on the floor (leaky cylinder valve) am I here to tell you about it. Tastes like acidic metal and black velvet rushes in.
I can only assume that it's still extremely risky because even if you remember to do it, you are very likely to misjudge how long you can hold your breath during an emergency situation with adrenaline pumping that requires you to drag someone up the stairs. Which means you get halfway up, end up forced to take a big deep breath, and pass out.
DO NOT hyperventilate before holding your breath and exerting yourself! Reason is, if you hyperventilate, then take a big breath, hold it and exert yourself you are likely to pass out _instantly_ w/o warning! [This was something we learned as kids - do not do this! You _will_ pass out (and you also risk embolism/stroke).
"Why is hyperventilating first bad?" - Should you hyperventilate and then hold your breath and any pressure is put on your lungs, YOU WILL PASS OUT! Don't do this!
Essentially hyperventilation reduces the blood's CO2 level. It becomes so low (while hyperventilating) that the body does not detect when the CO2 level subsequently rises to a dangerous level(while diving/holding your breath). The body fails to urge you to breathe fresh air and so you unwittingly pass out.
See the following two links for more info:
"The Choking Game: Self-induced hypocapnia": https://en.wikipedia.org/wiki/Choking_game#Self-induced_hypo...
Deep-water divers hyperventilate and then take a big breath immediately before they dive. Sometimes "shallow water blackout" (same as what happens to kids in the "choking game) occurs, endangering the diver:
Lake Nyos emitted a CO₂ cloud in 1986 which killed 1700 people.
The Apollo 13 LM canisters were rated for some 56 hours for two persons, but could only support three for less than 35 hours. That seems to fall somewhere between 5 and 6 kilograms, and apparently includes the scrubbers of the space suits onboard. Each suit was designed to support life for 6 hours (+ 30 minutes of emergency reserves) [3] which means some 350 grams of lithium hydroxide.
The longest EVA thus far lasted for just under 9 hours [4], for which you would need a bit more than 450 grams of lithium hydroxide. The Russian Orlan suits are designed to support life for between 5 and 7 hours [5].
An astronaut on an EVA might produce more carbon dioxide than the Wikipedia approximation, so you might want to round those numbers up.
Edit: I am also not sure how close to the theoretical maximum that absorption capacity is, so the numbers might really be somewhat optimistic.
[1] https://en.wikipedia.org/wiki/Lithium_hydroxide
[2] https://en.wikipedia.org/wiki/Carbon_dioxide#Human_physiolog...
[3] https://en.wikipedia.org/wiki/Apollo/Skylab_A7L
'Availability of lithium hydroxide (LiOH) for removing carbon dioxide presented a serious problem.'[1]
[1] https://en.wikipedia.org/wiki/Apollo_13#Crew_survival_and_re...
http://www.merriam-webster.com/dictionary/jerry%E2%80%93rigg...
Which is 'probably a blend of jerry-built and jury-rigged', so now I don't know what to believe.
Are you studying law or something, maybe Google is overly personalizing? :)
At Christmas time with about eight people it easily hit 1000ppm very quickly. Nobody else knew but I was watching the readings and it was interesting to see how that point it seems stuffy so a window was opened for some fresh air.
This is a 1970s single floor bungalow with forced air heating but no air exchange.
My intuition at first says that it would need to be a big hole because there won't be much airflow since the pressure inside and outside will be the same. But that is looking at it wrong.
It's the individual gases that matter. If CO2 is more concentrated inside than out, then there will be a net transfer of CO2 out. Similarly for O2 coming in. It's a diffusion problem, not an airflow problem, and I've got no usable intuition for that.
A interesting variant would be to make the hole intermittent. Assuming that my house is perfectly sealed when the doors are closed, do the normal openings for my daily comings and goings provide sufficient time for enough O2 to diffuse in and CO2 to diffuse out to keep my inside air breathable?
Let's assume CO2 transfer is entirely diffusion-limited, i.e. the worst-case of completely still air. The diffusive flux of some gas-component (per unit area per unit time) J is governed by concentration-gradient (dn/dx) multiplied by a magic diffusion coefficient D, which depends on the molecular properties of the gas. For CO2 in air D = 1.6e-5 m^2/s. Let's assume the gradient is linear so dn/dx = (n_{inside} - n_{outside}) / length. Now n_{outside) = 0.04% * 1 kg/m^3 = 4e-4 kg/m^3. We should decide what level of CO2 we can tolerate, 0.5% should be on the safe side, so n_{inside} = 5e-3 kg/m^3.
Length is a bit trickier. If (a) we assume completely stagnant air inside and outside, length should be chosen as the size of the box ~1 m say. However if (b) we assume that inside and outside are pretty well-mixed individually, due by breathing, wind etc., then length should be about the depth of the hole, or thickness of the box-material, say 1 cm = 0.01 m. For case (a) CO2 leaves our box at a rate of about 7e-8 kg/s/m^2, for (b) 7e-6 kg/s/m^2.
From the original article, a human breaths .84 kg of O2/day, let's estimate a production of 1kg CO2/day (the extra carbon atom can't be all that significant), or 1e-5 kg/s.
To compute the area of hole needed to maintain 0.5% CO2, we just divide 1e-5 by J, to get the area. In case (a) we need an enormous area of 135 m^2, in (b) "only" 1.35 m^2.
This seems to suggest that "air-holes" must work (if indeed they work at all) with air-flow. This doesn't necessary require an over- or under-pressure in the box - a suction can be generated by wind passing over a box with holes on both sides - this process would be far more efficient at restoring atmosphere than diffusion. But would be less reliable.
If that was overcome (e.g. with some weights or strings holding it down), it would be perfectly fine to breath in there for a while.
So, aside from the buoyancy issue, not only it's not "dumb", but that's exactly how old "diving bells" worked.
(Though I agree with coldtea that the PotC scene wasn't that bad.)
I think it'd float to the top though. It'll need some kind of weight...
A one ton metal boat shaped object would do:
http://kwc.org/mythbusters/2007/11/episode_92_pirates_2_row_...
> I think it'd float to the top though. It'll need some kind of weight...
A simple way of thinking about it is that boats float because they contain air (rather than water). The fact that they are upside down or the right way up changes little.
Since the rowboat can support two people, it should definitely float to the surface, dragging them along with it.
Only if the air bubble occupied the entire inner portion of the hull. If it were, say, only half the volume of the hull - I suspect it would be neutrally buoyant with the weight of two people.
*depending on depth and body composition, but give or take a bit, neutral.
But then, I'd expect the boat to break much sooner than they get out of air, or even completely under water.
http://www.huffingtonpost.com/2013/12/05/cook-survived-sunke...