Maybe my assumptions are wrong, and this is a truly curious question. I would ALWAYS expect floor to "basically" return the number in front of the ".", however close it is to another number. If you want that, you should use round().
Maybe my assumptions are wrong, and this is a truly curious question. I would ALWAYS expect floor to "basically" return the number in front of the ".", however close it is to another number. If you want that, you should use round().
Numbers will end up slightly lower or higher than an expected value simply due to accuracy in calculations and minor differences in input.
For example, suppose we have two UI elements, one with a width of 80% and the other expressed as a factor as 0.8. Depending on how specifically these are parsed and processed this may result in slightly different values. For the user creating the UI however they'd expect the same result.
The epsilons I introduce into my floor/ceil code is meant to deal with these minor variations.
Python only prints a decimal approximation to the true decimal value of the binary approximation stored by the machine. If Python were to print the true decimal value of the binary approximation stored for 0.1, it would have to display
>>> 0.1
0.1000000000000000055511151231257827021181583404541015625
That is more digits than most people find useful, so Python keeps the number of digits manageable by displaying a rounded value instead >>> 0.1
0.1
[1] https://docs.python.org/2/tutorial/floatingpoint.htmlInteresting is that print can show an exact representation of any floating point value, but of course 0.1 can't be represented exactly.
Not for negative numbers -- floor(-0.1) should be -1.