Factorizer
datapointed.net
datapointed.net
http://mathlesstraveled.com/2012/10/05/factorization-diagram...
(from the "About" page)
If you watched this website non-stop for a whole year, it would still only take a thousandth of a second or so to factorise the highest number you'd reach, from scratch. Integer factorisation is only time consuming when the numbers are really really big.
https://en.wikipedia.org/wiki/RSA_numbers
which was factored in 1991, so I bet you can get the right hardware and software to factor your number too. Maybe one of these implementations will do it:
https://en.wikipedia.org/wiki/General_number_field_sieve#Imp...
651651626268416641641703*983764598769387649827639876407 = 641071800653367850802176606120792275422168080497001121
Mathematica is really a pretty remarkable piece of software. I doubt it's world class for factorization, but it gives you easy access to a lot of pretty darn good algorithms for a wide range of problems.
There's 1 sentence on the implementation of FactorInteger in the docs, FWIW:
http://reference.wolfram.com/language/tutorial/SomeNotesOnIn...
http://pari.math.u-bordeaux.fr/
The relevant file is
src/basemath/ifactor1.c641071800653367850802176606120792275422168080497001121
OK, so take a 64 bit integer. That's the typical size of an integer in a modern programming language. A signed integer can represent 2^63-1 which is 9223372036854775807.
Imagine a "big integer" which is a composite of multiple 64-bit integers. With a big integer made up of two regular integers, you can represent the value 170141183460469231731687303715884105727. With three, you get to 3138550867693340381917894711603833208051177722232017256447 if I'm doing the math right. That's already in the ballpark of the number you mentioned - just three regular integers together.
Granted, I'm not talking about how difficult the factoring is, but it's worth noting that the size of the numbers are pretty small to a computer. Modern computers are really fast and can brute force a large number of computations. Mathematica probably has a fairly optimized general purpose factoring algorithm as well.
A number like this might be more difficult to factor:
16158503035655503650357438344334975980222051334857
74201606517271376232756943394544659860070576145673
18443589804609490097470597795752454605475440761932
24141560315438683650498045875098875194826053398028
81919203378413839610932130987808091904716923808523
52908229260181525214437879457705329043037761995619
65192760957166694834171210342487393282284747428088
01766316102903890282966551309635423015707512929643
20885583629718018592309286787991755761508229522018
48806616643615613562842355410104862578550863465661
73483927129032834896752299863417649931910776258319
47186677718010677166148023226592393024760740967779
26805529798115327You get problems with numbers over 100 digits. I recently entered a challenge where one of the questions involved prime factoring a 130 digit number. That was a record feat a couple of decades ago, now it takes a day or two on a modern computer.
Brute force search is O(N), the sieve of Eratosthenes is O(N log(log(N))). The Quadratic sieve is good up to 100 digits and runs in O(exp(sqrt(log n log log n))). Some utilities you can use for this are YAFU, MSIEVE or GGNFS.
//Link to original minified source code http://www.datapointed.net/media/2012/10/factor_min.js
//Credits to Stephen Von Worley www.datapointed.net
Here there is an expanded version https://gist.github.com/brianahearn/6032808 and a discussion: https://groups.google.com/forum/m/#!msg/mathfuture/yEfAaey6j...
I didn't make the visualization but I find the circles to be a good choice. Not only is it pretty, it makes use of two-dimensional space in a consistent way. A factor of 5 has the same shape whenever it appears.
If you factorized things into a straight line, do you just line everything up horizontally, in which case you just see hundreds of dots with gaps in them and there would be nothing interesting about the visualization? Or do you make rectangles, with some of the factors going vertically? In that case, sometimes your 5s will go horizontally and sometimes they'll go vertically, making a distinction out of nothing.
So for primes, you have a circle of groups of 1.