An Unusual Proof of the Doodle Theorem
solipsys.co.uk
solipsys.co.uk
Does this help?
http://www.solipsys.co.uk/new/GraphThreeColouring.html?HN2
Feel free to email if you'd prefer, I'll go and start reviewing it.
Thanks!
Edit: I've now added a side-box with that link.
Perhaps it is no longer a graph if I have a bidirectional edge? Or perhaps it is not considered planar if two edges coincide?
I'll add that - thanks!
Edit: now added - it will go live when the page updates.
Why should it be that a doodle is always two-colorable? It's a question a child could ask, but it leads to the whole area of graph theory. Personally, I find it a much better introduction to Graph Theory than the usual question about the Bridges of Königsberg:
https://en.wikipedia.org/wiki/Seven_Bridges_of_Königsberg
But there is a progression.
* A doodle is two-colorable
* A doodle is a planar, connected, Eulerian graph
* The dual of a planar, connected, Eulerian graph is bi-partite
* Bi-partite graphs are trivial to identify, and trivial to colour.
* What about tri-partite graphs?
* Identifying whether a given graph is tri-partite is NP-Complete.